PHP scandir 上的问题

我想请教一下各位会 php 的大大 /大佬们，小弟想利用 php scandir 的功能，在网页上显示某个资料夹的所有文件，但不知如何才可以仅在 output 时把文件的某个字词 删去，例如把以下"sample"删去。

$file

"; $i++; } } closedir($dh); ?>

output :

Sample-Apply.png

Sample-Banana.png

Sample-Cherry.png

----------------------- 以下是精选回复-----------------------

答:<?php
$path = ".";
$dh = opendir($path);
$i=1;
while (($file = readdir($dh)) !== false) {
if($file !="filelist.php" && $file != "." && $file != ".." && $file != "index.php" && $file != ".htaccess" && $file != "error_log" && $file != "cgi-bin") {
echo "<a href='$path/$file'>$file</a><br /><br />";
$i++;
}
}
closedir($dh);
?>
答:字符串查找
答:```
<?php
$path = ".";
$dh = opendir($path);
$i=1;
while (($file = readdir($dh)) !== false) {
if($file !="filelist.php" && $file != "." && $file != ".." && $file != "index.php" && $file != ".htaccess" && $file != "error_log" && $file != "cgi-bin") {
$file = str_replace("Sample-","",$file);
echo "<a href='$path/$file'>$file</a><br /><br />";
$i++;
}
}
closedir($dh);
?>
```
答:<?php
$path = ".";
$dh = opendir($path);
$i=1;
while (($file = readdir($dh)) !== false) {
if($file !="filelist.php" && $file != "." && $file != ".." && $file != "index.php" && $file != ".htaccess" && $file != "error_log" && $file != "cgi-bin") {
$name = str_replace("Sample-","",$file);
echo "<a href='$path/$file'>$name</a><br /><br />";
$i++;
}
}
closedir($dh);
?>